WebA, B and C are three points on a circle. Prove that the perpendicular bisectors of AB, BC and CA are concurrent. Answer: Given: A, B, C are 3 points on a circle Construction Draw perpendicular dissector of AB and AC and they meet at a point O. Then join OA, OB and OC. To prove: perpendicular bisector of AB, BC and CA are concurrent. WebMay 14, 2024 · Best answer. Let us understand that, two more points are said to be collinear if they all lie on a single straight line. Given: →AO + →OB = →BO + →OC A O → + O B …
Class 9 NCERT Solutions Maths Chapter 8 - Quadrilaterals
WebKali Bach. The the first example is not a right triangle because it does not follow the Pythagorean Theorem of a^2 + b^2 = c^2. AC^2+OC^2 doesn't equal AO^2. (11^2 + 5^2 = 13^2, which turns out to be 146 = 169, not true). Both … WebNov 26, 2024 · ABCD is a trapezium with AD ∥ BC and AD = 4cm. If the diagonals AC and BD intersect each other at O such that AO/OC = DO/OB =1/2, then BC = (a) 6cm (b) 7cm (c) 8cm (d) 9cm cbse class-10 1 Answer +1 vote answered Nov 26, 2024 by Ankurgupta (53.8k points) selected Nov 28, 2024 by AmitMukherjee Best answer (c) 8cm In triangles ΔAOD … shown in red
Cho tam giác ABC cân tại A có góc BAC = 30 độ, vẽ tia Bx vuông …
WebNov 17, 2024 · Step-by-step explanation: This is your answer according to my promise Advertisement New questions in Math 1. 1+a+b+ ab can be written as (a) a (b + 1) (b) b … WebMar 22, 2024 · Δ AOD ≅ Δ BOC (From 1st part) ∠ OAD = ∠ OBC (CPCT) But ∠ OAD & ∠ OBC and these form a pair of alternate angles If a transversal intersects two lines such that pair of alternate interior angles … WebApr 16, 2024 · Given: In ⊙O, OC ⊥ AB and OC = 9. Find the following. (a) AB (b) BC Consider the following figure. A circle has center point O. There are 3 points on the circle … shown in malay